Решение к #Задача6: SELECT lower(e.last_name || ' ' || e.firs | SQL задачи
Решение к #Задача6:
SELECT lower(e.last_name || ' ' || e.first_name) AS lower, upper(e.last_name || ' ' || e.first_name) AS upper, initcap(e.last_name || ' ' || e.first_name) AS initcap FROM employee e ORDER BY e.last_name, e.first_name